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FAQ-Why Can the Rate Reaches 11.1 G When the LSX Is Configured with 10 GE-LAN Services and the Mapping Mode of the Client Side is Bit Transparency

Publication Date:  2012-07-25 Views:  37 Downloads:  0
Issue Description
Q:
When the LSX is configured with 10 GE-LAN services, and when the service mapping mode of the client side is bit transparency (at the rate of 11.1 Gbit/s), the rate reaches 11.1 Gbit/s. Why?
Alarm Information
Null.
Handling Process

A:
The rate is 10.3125 Gbit/s when the signal type is 10GE LAN. Regardless of OTU1, OTU2, and OTU3, the OTN frame structure is fixed (four rows and 4080 columns). Except the 256-column FEC area and the 16-column overhead area of OTU2, ODU2, and OPU2, the OPU2 area occupies 3808 columns. When the client-side signals are mapped into OPU2 payloads, the OPU2 payloads must be added to the 16-column fixed stuff (FS). Therefore, in the OTU2 frame structure, client-side signals occupy 3792 (3808 - 16) columns. The OTN frame frequency can be adjusted. To implement transparent transmission of all 10GE-LAN signals of 10.3125Gbit/s without any change through OTU2 frames, the OTU2e rate on the WDM side is obtained though the following formula:

3792/4080 = 10.3125/OTU2e frame rate

That is, OTU2e frame rate = 255/237 × 10.3125 kbit/s = 11.0957 Gbit/s = 11.1 Gbit/s 
Root Cause
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Suggestions
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