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Configuration Guide - Device Management

CloudEngine 8800, 7800, 6800, and 5800 V200R005C10

This document describes the configurations of Device Management, including device status query, hardware management, Information Center Configuration, NTP, Synchronous Ethernet Configuration, Fault Management Configuration, Energy-Saving Management Configuration, Performance Management Configuration, Maintenance Assistant Configuration, and OPS Configuration.
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Clock Synchronization Implementation

Clock Synchronization Implementation

  • The frequency restored using 1588v2 messages is less accurate than the frequency restored using synchronous Ethernet. If possible, it is recommended that you use synchronous Ethernet for frequency synchronization and use 1588v2 for time synchronization.
  • For details about 1588v2 clock synchronization, see Synchronous Ethernet Configuration.

1588v2 can also be used for clock synchronization in addition to time synchronization. That is, 1588v2 messages can be used to restore the frequency.

The master node periodically sends a Sync message to the slave node. The message carries the timestamp when the master node sends the Sync message. Each time the slave node receives a Sync message, it generates a timestamp. When the link delay is stable, the two timestamps change at the same pace. If the receiving timestamp changes faster or slower, the clock of the receiving device runs faster or slower than the clock of the sending device. In this case, the local clock of the receiving device needs to be adjusted. In this manner, the two devices are synchronized to the same frequency.

In Figure 6-13, NodeA needs to synchronize the time with NodeB. If the link delay and resident time are not counted and the frequencies of NodeA and NodeB are the same, NodeA and NodeB should have the same accumulated time difference within a specified period, that is, t2N - t20 = t1N - t10. If the time difference (t2N - t20) is larger than the time difference (t1N - t10), the frequency of NodeA is higher than the frequency of NodeB and needs to be reduced by the value of [(t2N - t20) - (t1N - t10)]/2. If the time difference (t2N - t20) is smaller than the time difference (t1N - t10), the frequency of NodeA is lower than the frequency of NodeB and needs to be increased by the value of [(t2N - t20) - (t1N - t10)]/2.

Figure 6-13 Clock synchronization

Updated: 2019-04-20

Document ID: EDOC1100075362

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